Multinomial Distribution

Suppose the random variables X1,X2,…,XkX_1, X_2, \ldots, X_k represent the number of times each outcome θ1,θ2,…,θk\theta_1, \theta_2, \ldots, \theta_k occurs in nn independent trials.

These random variables are said to follow a multinomial distribution with parameters nn and p=(p1,p2,…,pk)\mathbf{p} = (p_1, p_2, \ldots, p_k) iff the following conditions are met:

∑i=1kpi=1\sum_{i=1}^{k} p_i = 1 ∑i=1kxi=n\sum_{i=1}^{k} x_i = n P(X1=x1,X2=x2,…,Xk=xk)=n!x1! x2! ⋯ xk! p1x1 p2x2 ⋯ pkxkP(X_1 = x_1, X_2 = x_2, \ldots, X_k = x_k) = \frac{n!}{x_1! \, x_2! \, \cdots \, x_k!} \, p_1^{x_1} \, p_2^{x_2} \, \cdots \, p_k^{x_k} (nx1,x2,…,xk)=n!x1! x2! ⋯ xk!\binom{n}{x_1, x_2, \ldots, x_k}= \frac{n!}{x_1! \, x_2! \, \cdots \, x_k!}

Mean and Variance

For each outcome ii:

μXi=npi\mu_{X_i} = np_i σXi2=npi(1−pi)\sigma^2_{X_i} = np_i(1 - p_i)

Relation to Binomial

The binomial distribution is a special case with k=2k = 2 outcomes (success and failure).

Written by September 29, 2026 1 min read
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