Logarithm

Work in progress. This note is still being written and incomplete.

For a non-zero complex number zz, logz\log z is the set of all wCw \in \mathbb{C} with ew=ze^w = z.

Writing z=reiθz = re^{i\theta} with r=zr = |z| and w=u+ivw = u + iv, the condition ew=ze^w = z gives eu=re^u = r and vargzv \in \arg z. So

logz=lnz+iargz={lnz+i(Argz+2kπ):kZ},z0\log z = \ln|z| + i\arg z = \{\,\ln|z| + i(\operatorname{Arg} z + 2k\pi) : k \in \mathbb{Z}\,\}, \qquad z \ne 0

Here:

  • Argz\operatorname{Arg} z: principal argument of zz, the unique argument with π<Argzπ-\pi < \operatorname{Arg} z \le \pi
  • argz={Argz+2kπ:kZ}\arg z = \{\operatorname{Arg} z + 2k\pi : k \in \mathbb{Z}\}

logz\log z is multi-valued.

Principal Value

The logarithm value deduced by setting k=0k=0.

Logz=lnz+iArgz,z0\operatorname{Log} z = \ln|z| + i\operatorname{Arg} z, \qquad z \ne 0

Below you can change zz and see how Log(z)\operatorname{Log}(z) changes.

Re Im 2.24 e0.46i Log z = 0.80 + 0.46i

Properties

Let z1z_1 and z2z_2 be non-zero.

  • log(z1z2)=logz1+logz2\log(z_1 z_2) = \log z_1 + \log z_2
  • logz1z2=logz1logz2\log\dfrac{z_1}{z_2} = \log z_1 - \log z_2
  • log1z=logz\log\dfrac{1}{z} = -\log z

Examples

log(1+i)\log(1+i)

  • 1+i=2|1+i| = \sqrt{2}
  • Arg(1+i)=π4\operatorname{Arg}(1+i) = \dfrac{\pi}{4}
log(1+i)=12ln2+i(π4+2kπ),kZ\log(1+i) = \dfrac{1}{2}\ln 2 + i\left(\dfrac{\pi}{4} + 2k\pi\right), \qquad k \in \mathbb{Z} Log(1+i)=12ln2+iπ4\operatorname{Log}(1+i) = \dfrac{1}{2}\ln 2 + i\dfrac{\pi}{4}

logi\log i

  • i=1|i| = 1
  • Arg(i)=π2\operatorname{Arg}(i) = \dfrac{\pi}{2}
logi=i(π2+2kπ),kZ\log i = i\left(\dfrac{\pi}{2} + 2k\pi\right), \qquad k \in \mathbb{Z} Logi=iπ2\operatorname{Log} i = i\dfrac{\pi}{2}
Written by September 13, 2026 2 min read
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