Derivatives

Work in progress. This note is still being written and incomplete.

3 min read Last updated Sun Sep 06 2026 13:01:26 GMT+0000 (Coordinated Universal Time)

Let ff be a function whose domain contains a neighborhood zz0<ϵ|z-z_0| < \epsilon of z0z_0. The derivative of ff at z0z_0 is

f(z0)=limzz0f(z)f(z0)zz0f'(z_0) = \lim_{z \to z_0} \frac{f(z)-f(z_0)}{z-z_0}

provided this limit exists. ff is differentiable at z0z_0 when f(z0)f'(z_0) exists.

If ff is differentiable at z0z_0, then ff is continuous at z0z_0.

Differentiation Formulas

Let cCc \in \mathbb{C}, and let ff, gg be functions differentiable at zCz \in \mathbb{C}. Then:

  • ddzc=0\dfrac{\text{d}}{\text{d}z}\,c = 0
  • ddz(cf(z))=cf(z)\dfrac{\text{d}}{\text{d}z}\,(cf(z)) = cf'(z)
  • ddzzn=nzn1\dfrac{\text{d}}{\text{d}z}\,z^n = nz^{n-1}, for positive integer nn
  • ddz(f(z)+g(z))=f(z)+g(z)\dfrac{\text{d}}{\text{d}z}\,(f(z)+g(z)) = f'(z)+g'(z)
  • ddz(f(z)g(z))=f(z)g(z)+f(z)g(z)\dfrac{\text{d}}{\text{d}z}\,(f(z)g(z)) = f(z)g'(z)+f'(z)g(z)
  • ddzf(z)g(z)=g(z)f(z)f(z)g(z)(g(z))2\dfrac{\text{d}}{\text{d}z}\,\dfrac{f(z)}{g(z)} = \dfrac{g(z)f'(z)-f(z)g'(z)}{(g(z))^2}, provided g(z)0g(z) \ne 0

Cauchy-Riemann Equations

Let f(z)=u(x,y)+iv(x,y)f(z) = u(x,y)+iv(x,y), and suppose f(z0)f'(z_0) exists at z0=x0+iy0z_0 = x_0+iy_0. Then the first-order partial derivatives of uu and vv exist at (x0,y0)(x_0,y_0) and satisfy

ux=vy,uy=vxu_x = v_y, \qquad u_y = -v_x

at (x0,y0)(x_0,y_0), and

f(z0)=ux(x0,y0)+ivx(x0,y0)f'(z_0) = u_x(x_0,y_0)+iv_x(x_0,y_0)

The equations follow from forcing the derivative limit to agree along the real and imaginary directions of approach.

The equations are necessary but not sufficient. They can hold at z0z_0 while f(z0)f'(z_0) does not exist. See Sufficient Conditions for Differentiability.

The Jacobian of (x,y)(u,v)(x,y) \mapsto (u,v) is then

(uxvxvxux)\begin{pmatrix} u_x & -v_x \\ v_x & u_x \end{pmatrix}

which acts as multiplication by ux+ivxu_x + iv_x. A complex-differentiable map is locally a rotation plus a uniform scaling.

Examples:

  • f(z)=z2f(z) = z^2: ux=vy=2xu_x = v_y = 2x, uy=vx=2yu_y = -v_x = -2y, and f(z)=2x+i2y=2zf'(z) = 2x + i2y = 2z.
  • f(z)=zˉf(z) = \bar{z}: ux=1u_x = 1, vy=1v_y = -1, so the equations fail everywhere and zˉ\bar{z} is nowhere differentiable.

Sufficient Conditions for Differentiability

Let f(z)=u(x,y)+iv(x,y)f(z) = u(x,y)+iv(x,y) be defined throughout a neighborhood UU of z0=x0+iy0z_0 = x_0+iy_0. f(z0)f'(z_0) exists iff:

  • The first-order partial derivatives of uu and vv with respect to xx and yy exist everywhere in UU.
  • Those partial derivatives are continuous at (x0,y0)(x_0,y_0) and satisfy the Cauchy-Riemann equations at (x0,y0)(x_0,y_0).

When these hold,

f(z0)=ux(x0,y0)+ivx(x0,y0)f'(z_0) = u_x(x_0,y_0)+iv_x(x_0,y_0)

Polar Form of the Cauchy-Riemann Equations

Let f(z)=u(r,θ)+iv(r,θ)f(z) = u(r,\theta)+iv(r,\theta) be defined throughout a neighborhood of a non-zero point z0=r0eiθ0z_0 = r_0e^{i\theta_0}. f(z0)f'(z_0) exists iff:

  • The first-order partial derivatives of uu and vv with respect to rr and θ\theta exist everywhere in the corresponding polar-coordinate neighborhood.
  • Those partial derivatives are continuous at (r0,θ0)(r_0,\theta_0) and satisfy
rur=vθ,uθ=rvrru_r = v_\theta, \qquad u_\theta = -rv_r

at (r0,θ0)(r_0,\theta_0).

When these hold,

f(z0)=eiθ0(ur(r0,θ0)+ivr(r0,θ0))f'(z_0) = e^{-i\theta_0}(u_r(r_0,\theta_0)+iv_r(r_0,\theta_0))
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