Kinetic Analysis

D’Alembert’s Principle

By this principle, a particle or a system of particles moving with a constant acceleration is known as in dynamic equilibrium.

For a Particle

F−ma=0F - ma = 0
Here:
FF
resultant applied force
mm
mass of the particle
aa
acceleration of the particle

mama is known as the inertia force which is fictious.

For a System of Particles

The equation can be rewritten as:

F=∑miai=F=maGF = \sum m_ia_i = F = ma_G
Here:
FF
resultant applied force
mim_i
mass of a particle
aia_i
acceleration of a particle
mm
total mass
aGa_G
acceleration of the center of mass

Kinetics of a Rigid Body

Both translational and rotational aspects of the motion must be considered.

F=ma      and      M=IαF=ma \;\;\; \text{and} \;\;\; M=I\alpha
Here:
FF
resultant applied force
mm
mass of the body
aa
acceleration of the body
MM
moment of the resultant force
II
mass moment of inertia
α\alpha
angular acceleration of the body

General Plane Motion

∑MG=IGα\sum M_G = I_G \alpha
Here:
MGM_G
moment about center of mass
IGI_G
mass moment of inertia about center of mass
α\alpha
angular acceleration of the body

Let OO be a point other than GG.

∑MO=IGα+maGrOG\sum M_O = I_G \alpha + ma_G r_{OG}

Kinetic Energy

T=translational kinetic energy+rotational kinetic energyT = \text{translational kinetic energy} + \text{rotational kinetic energy} T=12mvG2+12IGω2T = \frac{1}{2}mv_G^2 + \frac{1}{2}I_G\omega^2

Center of Percussion

The point on an object attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.

Translational and rotational motions cancel at the pivot when an impulsive blow is struck at the center of percussion.

lP/G=kG2OGl_{\text{P/G}} = \frac{k_\text{G}^2}{\text{OG}}
Here:
P\text{P}
Center of percussion
G\text{G}
Center of gravity
O\text{O}
Pivot

For a uniform rod:

lP/G=L6l_{\text{P/G}} = \frac{L}{6}
Written by November 3, 2026 2 min read
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