Fourier Series

Used for periodic non-sinusoidal waveforms. Suppose the periodic time is TT. The waveform can be represented as a sum of sine wave. The sine waves have integer multiple of the original frequency f0=2π/Tf_0 = 2\pi / T.

f(t)=a02+∑n=1∞[ancos⁡(f0nt)+bnsin⁡(f0nt)]f(t) = \frac{a_0}{2} + \sum_{n=1}^{\infty} \big[ a_n \cos\left(f_0 nt\right) + b_n \sin\left(f_0 nt\right) \big]

Useful Trigonometric Integrals

∫ττ+Tcos⁡(f0nt) dt=∫ττ+Tsin⁡(f0nt) dt=0\int_{\tau}^{\tau + T} \cos(f_0 nt)\, \text{d}t = \int_{\tau}^{\tau + T} \sin(f_0 nt)\, \text{d}t = 0 ∫ττ+Tsin⁡(f0nt)cos⁡(f0mt) dt=0\int_{\tau}^{\tau + T} \sin(f_0 nt) \cos(f_0 mt) \, \text{d}t = 0 ∫ττ+Tsin⁡(f0nt)sin⁡(f0mt) dt={T2if n=m0otherwise\int_{\tau}^{\tau + T} \sin(f_0 nt) \sin(f_0 mt) \, \text{d}t = \begin{cases} \frac{T}{2} & \text{if } n = m \\ 0 & \text{otherwise} \end{cases} ∫ττ+Tcos⁡(f0nt)cos⁡(f0mt) dt={T2if n=m0otherwise\int_{\tau}^{\tau + T} \cos(f_0 nt) \cos(f_0 mt) \, \text{d}t = \begin{cases} \frac{T}{2} & \text{if } n = m \\ 0 & \text{otherwise} \end{cases}

Unknown Coefficients

∀n≥0\forall n \geq 0.

an=2T∫ττ+Tf(t)cos⁡(nf0t) dta_n = \frac{2}{T} \int_{\tau}^{\tau + T} f(t)\cos(nf_0t) \, \text{d}t bn=2T∫ττ+Tf(t)sin⁡(nf0t) dtb_n = \frac{2}{T} \int_{\tau}^{\tau + T} f(t)\sin(nf_0t)\, \text{d}t

a02\frac{a_0}{2} is the DC offset.

Symmetry

For any waveform, subtracting the DC offset results in a symmetrical waveform.

Even Symmetry

When a wave is symmetric about the vertical axis.

f(t)=f(−t)f(t) = f(-t)

The fourier series of an even waveform contains only cosine terms.

an=4T∫ττ+T/2f(t)cos⁡(nf0t) dt    and    bn=0a_n = \frac{4}{T} \int_{\tau}^{\tau + T/2} f(t)\cos(nf_0t) \, \text{d}t \;\;\text{and}\;\; b_n = 0

Odd Symmetry

When a wave is symmetric about the origin.

f(t)=−f(−t)f(t) = -f(-t)

The fourier series of an odd waveform contains only sine terms.

an=0    and    bn=4T∫ττ+T/2f(t)sin⁡(nf0t) dta_n = 0 \;\;\text{and}\;\; b_n = \frac{4}{T} \int_{\tau}^{\tau + T/2} f(t)\sin(nf_0t) \, \text{d}t

Half-Wave Symmetry

When a wave repeats itself with a reversal of sign after half a period.

f(t)=−f(t+T2)=−f(t−T2)f(t) = -f(t + \frac{T}{2}) = -f(t - \frac{T}{2})

The coefficients can be found by:

an={4T∫ττ+T/2f(t)cos⁡(nf0t) dtif n is odd0if n is evena_n = \begin{cases} \frac{4}{T} \int_{\tau}^{\tau + T/2} f(t)\cos(nf_0t) \, \text{d}t & \text{if } n \text{ is odd} \\ 0 & \text{if } n \text{ is even} \end{cases} bn={4T∫ττ+T/2f(t)sin⁡(nf0t) dtif n is odd0if n is evenb_n = \begin{cases} \frac{4}{T} \int_{\tau}^{\tau + T/2} f(t)\sin(nf_0t) \, \text{d}t & \text{if } n \text{ is odd} \\ 0 & \text{if } n \text{ is even} \end{cases}

Half-wave symmetry can co-exist with odd symmetry or even symmetry. In that case:

an={8T∫ττ+T/4f(t)cos⁡(nf0t) dtif n is odd0if n is evena_n = \begin{cases} \frac{8}{T} \int_{\tau}^{\tau + T/4} f(t)\cos(nf_0t) \, \text{d}t & \text{if } n \text{ is odd} \\ 0 & \text{if } n \text{ is even} \end{cases} bn={8T∫ττ+T/4f(t)sin⁡(nf0t) dtif n is odd0if n is evenb_n = \begin{cases} \frac{8}{T} \int_{\tau}^{\tau + T/4} f(t)\sin(nf_0t) \, \text{d}t & \text{if } n \text{ is odd} \\ 0 & \text{if } n \text{ is even} \end{cases}

Frequency Spectrum

Plot of harmonic number vs frequency.

Harmonic Number

nnth harmonic number denotes the amplitude or strength of the nnth harmonic. Denoted as hnh_n.

∣hn∣=an2+bn2    and    phase angle=tan⁡−1(bnan)|h_n| = \sqrt{a_n^2 + b_n^2} \;\;\text{and}\;\; \text{phase angle} = \tan^{-1}\left(\frac{b_n}{a_n}\right)

RMS

yrms2=a02+∑i=0∞[ai,rms2+bi,rms2]y_{\text{rms}}^2 = a_0^2 + \sum_{i=0}^\infty \Big[ a_{i,\text{rms}}^2 + b_{i,\text{rms}}^2 \Big]

Total Harmonic Distortion

A measurement of the distortion present in the waveform compared to the original waveform.

yTHD=1h1∑i=2∞hi2y_{\text{THD}} = \frac{1}{h_1} \sqrt{\sum_{i=2}^\infty h_i^2}

Here hih_i is the rms of iith harmonic. DC offset is ignored. Usually given as a percentage.

Complex Form

f(t)=∑n=−∞∞Cnejnf0tf(t) =\sum_{n=-\infty}^{\infty} C_n e^{jnf_0t}

Here CnC_n can be found by:

Cn=An−jBn2=1T∫ττ+Tf(t)e−jnf0t dtC_n = \frac{A_n - jB_n}{2} =\frac{1}{T} \int_{\tau}^{\tau + T} f(t)e^{-jnf_0 t}\,\text{d}t
Written by September 29, 2026 2 min read
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