Theorems

Mean Value Theorem

Let

  • δ>0\delta > 0
  • D={(x,y)∈R2:(x−a)2+(y−b)2<δ}D = \big\{ (x,y) \in \mathbb{R}^2 : (x-a)^2 + (y-b)^2 \lt \delta \big\}
  • f:D→Rf : D \rightarrow \mathbb{R}
  • (a,b)∈D(a,b) \in D
  • fxf_x and fyf_y exists

Then ∃θ,α∈(0,1)\exists \theta, \alpha \in (0,1) such that:

Δf=f(Px,Py)−f(a,b)=Δxfx(a+θΔx,b)+Δyfy(a+Δx,b+αΔy)\Delta f = f(P_x, P_y) - f(a,b) = \Delta{x} f_x (a+\theta \Delta{x}, b) + \Delta{y} f_y (a+\Delta{x}, b+\alpha \Delta{y})

Schwarz’s Theorem

Also known as Clairaut’s theorem on equality of mixed partials. Let D⊂R2D \subset \mathbb{R}^2 be open. Let f:D→Rf: D \rightarrow \mathbb{R}. If fxyf_{xy} and fyxf_{yx} are continous on DD then fxy=fyxf_{xy}=f_{yx}.

Written by October 17, 2026 1 min read
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