Linear Differential Equations
dxndny+p1(x)dxn−1dn−1y+...+pn(x)y=q(x)
Based on q(x), the above equation is categorized into 2 types:
- Homogenous if q(x)=0
- Non-homogenous if q(x)=0
Solution
The general solution of the equation is y=yp+yc.
Here
- yp - particular solution
- yc - complementary solution
Particular solution
Doesn’t exist for homogenous equations. For non-homogenous equations check
steps section of 2nd order ODE.
Complementary solution
Solutions assuming LHS=0 (as in a homogenous equation).
yc=i=1∑nciyi
Here
- ci - constant coefficients
- yi - a linearly-independent solution
Linearly dependent & independent
n-th order linear differential equations have n linearly independent
solutions.
Two solutions of a differential equation u,v are said to be linearly
dependent, if there exists constants c1,c2(=0) such that
c1u(x)+c2v(x)=0.
Otherwise, the solutions are said to be linearly independent, which means:
i=1∑nciyi=0⟹∀ci=0
Linear differential operators with constant coefficients
Differential operator
Defined as:
Di=dxidi;n∈Z+
The above equation can be written using the differential operator:
Dny+a1Dn−1y+...+any=q(x)
Here if y is factored out (how tf?):
(Dn+a1Dn−1+...+an)y=P(D)y=q(x)
where P(D)=(Dn+a1Dn−1+...+an).
P(D) is called a polynomial differential operator with constant
coefficients.