Generlized IVT

1 min read Updated Fri Apr 24 2026 03:46:02 GMT+0000 (Coordinated Universal Time)

Suppose f,gf,g are continuous functions on [a,b][a,b] and g0g \ge 0. Then x(a,b)\exists x \in (a,b):

f(x)abg=abfgf(x) \int_a^b g = \int_a^b fg